WebFind the focus, directrix, and focal diameter of the parabola. y2 = 8x. write the equations of the parabola, the directrix, and the axis of symmetry. vertex: (-4,2) focus: (-4,6) if … WebStep 1: Standardize the given equation. The equation y 2 + 4 x + 4 y + k = 0 of the parabola is given. Standardize the given equation as follows: Add and subtract 4 from the Left-hand side. y 2 + 4 x + 4 y + k + 4 - 4 = 0 ⇒ y 2 + 4 y + 4 + 4 x + k - 4 = 0 ⇒ y + 2 2 = 4 - 4 x - k ⇒ y + 2 2 = - 4 x + - 4 + k 4 ... 1
The equation y^2 + 4x + 4y + k = 0 represents a parabola …
WebMar 28, 2024 · Equation of the directrix: y = -a Equation of axis: x = 0 Length of the latus rectum: 4a Focal distance of a point P (x, y): a + y 4. x2 = – 4ay Here, Coordinates of vertex: (0, 0) Coordinates of focus: (0, -a) Equation of the directrix: y = a Equation of axis: x = 0 Length of the latus rectum: 4a Focal distance of a point P (x, y): a – y WebJan 26, 2016 · The focus is at (1,3), the vertex is (2,3) and the directrix is at x = 3 Explanation: Reformulate the equation to have one variable on its own on the left hand side. In this case it should be x because y is the one that is raised to a power. y2 + 4x − 4y −8 = 0 4x = −y2 + 4y +8 x = − 1 4(y2 −4y − 8) cipher\\u0027s si
A parabola with focus (3, 0) and directrix x = –3. Points P and Q …
WebThen graph the parabola. y^2 = 4x; Find the vertex, focus, directrix, and axis of symmetry of the parabola (y - 1)^2 = 16x. Find directrix focus and axis for the parabola y^2 + 8x - 6y + 1 = 0. Find the focus and directrix of the parabola given by the equation y = 2 x^2 - 3 x + 10. Find the equation of a parabola with directrix x = 2 and focus ... WebQuestion: QUESTION 1 Find the focus and directrix of the parabola with the given equation. y^(2)=4x. QUESTION 1 Find the focus and directrix of the parabola with the given equation. y^(2)=4x. Expert Answer. Who are the experts? Experts are tested by Chegg as specialists in their subject area. We reviewed their content and use your … WebTherefore, the equation of the parabola can be written in vertex form as: (x-8)^2 = 4p (y-7) where p=3 is the distance from the vertex to the focus (or directrix). Simplifying this … cipher\\u0027s sh